3-(n-21)=6(n+5)

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Solution for 3-(n-21)=6(n+5) equation: 



3-(n-21)=6(n+5)

We move all terms to the left:

3-(n-21)-(6(n+5))=0

We get rid of parentheses

-n-(6(n+5))+21+3=0



We calculate terms in parentheses: -(6(n+5)), so:

6(n+5)

We multiply parentheses

6n+30

Back to the equation:

-(6n+30)



We add all the numbers together, and all the variables

-1n-(6n+30)+24=0

We get rid of parentheses

-1n-6n-30+24=0

We add all the numbers together, and all the variables

-7n-6=0

We move all terms containing n to the left, all other terms to the right

-7n=6

n=6/-7

n=-6/7

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