3-(p-4)=2(p+6)

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Solution for 3-(p-4)=2(p+6) equation: 



3-(p-4)=2(p+6)

We move all terms to the left:

3-(p-4)-(2(p+6))=0

We get rid of parentheses

-p-(2(p+6))+4+3=0



We calculate terms in parentheses: -(2(p+6)), so:

2(p+6)

We multiply parentheses

2p+12

Back to the equation:

-(2p+12)



We add all the numbers together, and all the variables

-1p-(2p+12)+7=0

We get rid of parentheses

-1p-2p-12+7=0

We add all the numbers together, and all the variables

-3p-5=0

We move all terms containing p to the left, all other terms to the right

-3p=5

p=5/-3

p=-1+2/3

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