3-(x+2)=2(x-3)-3(x-2)

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Solution for 3-(x+2)=2(x-3)-3(x-2) equation: 



3-(x+2)=2(x-3)-3(x-2)

We move all terms to the left:

3-(x+2)-(2(x-3)-3(x-2))=0

We get rid of parentheses

-x-(2(x-3)-3(x-2))-2+3=0



We calculate terms in parentheses: -(2(x-3)-3(x-2)), so:

2(x-3)-3(x-2)

We multiply parentheses

2x-3x-6+6

We add all the numbers together, and all the variables

-x

Back to the equation:

-(-x)



We add all the numbers together, and all the variables

-x-(-1x)-2+3=0

We add all the numbers together, and all the variables

-1x-(-1x)+1=0

We get rid of parentheses

-1x+1x+1=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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