3-(x+2)=9-3(x-1)

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Solution for 3-(x+2)=9-3(x-1) equation: 



3-(x+2)=9-3(x-1)

We move all terms to the left:

3-(x+2)-(9-3(x-1))=0

We get rid of parentheses

-x-(9-3(x-1))-2+3=0



We calculate terms in parentheses: -(9-3(x-1)), so:

9-3(x-1)

determiningTheFunctionDomain
-3(x-1)+9

We multiply parentheses

-3x+3+9

We add all the numbers together, and all the variables

-3x+12

Back to the equation:

-(-3x+12)



We add all the numbers together, and all the variables

-1x-(-3x+12)+1=0

We get rid of parentheses

-1x+3x-12+1=0

We add all the numbers together, and all the variables

2x-11=0

We move all terms containing x to the left, all other terms to the right

2x=11

x=11/2

x=5+1/2

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