3-(x+5)=-30+(x+4)

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Solution for 3-(x+5)=-30+(x+4) equation: 



3-(x+5)=-30+(x+4)

We move all terms to the left:

3-(x+5)-(-30+(x+4))=0

We get rid of parentheses

-x-(-30+(x+4))-5+3=0



We calculate terms in parentheses: -(-30+(x+4)), so:

-30+(x+4)

determiningTheFunctionDomain
(x+4)-30

We get rid of parentheses

x+4-30

We add all the numbers together, and all the variables

x-26

Back to the equation:

-(x-26)



We add all the numbers together, and all the variables

-1x-(x-26)-2=0

We get rid of parentheses

-1x-x+26-2=0

We add all the numbers together, and all the variables

-2x+24=0

We move all terms containing x to the left, all other terms to the right

-2x=-24

x=-24/-2

x=+12

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