3-(x-2)=1/2(x+3)

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Solution for 3-(x-2)=1/2(x+3) equation: 



3-(x-2)=1/2(x+3)

We move all terms to the left:

3-(x-2)-(1/2(x+3))=0



Domain of the equation: 2(x+3))!=0

x∈R



We get rid of parentheses

-x-(1/2(x+3))+2+3=0

We multiply all the terms by the denominator


-x*2(x+3))-(1+2*2(x+3))+3*2(x+3))=0

We add all the numbers together, and all the variables

-x*2(x+3))-(1+2*2(x+3))+3*2(x=0

Wy multiply elements

-2x^2(x+8x^2(x=0

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