3-(x-3)=4+(x-2)

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Solution for 3-(x-3)=4+(x-2) equation: 



3-(x-3)=4+(x-2)

We move all terms to the left:

3-(x-3)-(4+(x-2))=0

We get rid of parentheses

-x-(4+(x-2))+3+3=0



We calculate terms in parentheses: -(4+(x-2)), so:

4+(x-2)

determiningTheFunctionDomain
(x-2)+4

We get rid of parentheses

x-2+4

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We add all the numbers together, and all the variables

-1x-(x+2)+6=0

We get rid of parentheses

-1x-x-2+6=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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