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3-(x-5)=8+2(x+9)
We move all terms to the left:
3-(x-5)-(8+2(x+9))=0
We get rid of parentheses
-x-(8+2(x+9))+5+3=0
We calculate terms in parentheses: -(8+2(x+9)), so:We add all the numbers together, and all the variables
8+2(x+9)
determiningTheFunctionDomain 2(x+9)+8
We multiply parentheses
2x+18+8
We add all the numbers together, and all the variables
2x+26
Back to the equation:
-(2x+26)
-1x-(2x+26)+8=0
We get rid of parentheses
-1x-2x-26+8=0
We add all the numbers together, and all the variables
-3x-18=0
We move all terms containing x to the left, all other terms to the right
-3x=18
x=18/-3
x=-6
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