3-1-3z/2=9/10+8z

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Solution for 3-1-3z/2=9/10+8z equation: 



3-1-3z/2=9/10+8z

We move all terms to the left:

3-1-3z/2-(9/10+8z)=0



Domain of the equation: 10+8z)!=0

We move all terms containing z to the left, all other terms to the right

8z)!=-10

z!=-10/1

z!=-10

z∈R



We add all the numbers together, and all the variables

-3z/2-(+8z+9/10)+3-1=0

We add all the numbers together, and all the variables

-3z/2-(+8z+9/10)+2=0

We get rid of parentheses

-3z/2-8z+2-9/10=0

We calculate fractions

There is no solution for this equation

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