3-1/2(4-x)=2+1/4(5+x)

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Solution for 3-1/2(4-x)=2+1/4(5+x) equation: 



3-1/2(4-x)=2+1/4(5+x)

We move all terms to the left:

3-1/2(4-x)-(2+1/4(5+x))=0



Domain of the equation: 2(4-x)!=0

x∈R





Domain of the equation: 4(5+x))!=0

x∈R



We add all the numbers together, and all the variables

-1/2(-1x+4)-(2+1/4(x+5))+3=0

We calculate fractions


(-4xx/(2(-1x+4)*4(x+5)))+(-2x0/(2(-1x+4)*4(x+5)))+3=0



We calculate terms in parentheses: +(-4xx/(2(-1x+4)*4(x+5))), so:

-4xx/(2(-1x+4)*4(x+5))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)





We calculate terms in parentheses: +(-2x0/(2(-1x+4)*4(x+5))), so:

-2x0/(2(-1x+4)*4(x+5))

We multiply all the terms by the denominator


-2x0

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

-4xx-2x+3=0

We add all the numbers together, and all the variables

-2x-4xx+3=0

We move all terms containing x to the left, all other terms to the right

-2x-4xx=-3

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