3-2(1+2x)=1-8(x-2)

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Solution for 3-2(1+2x)=1-8(x-2) equation: 



3-2(1+2x)=1-8(x-2)

We move all terms to the left:

3-2(1+2x)-(1-8(x-2))=0

We add all the numbers together, and all the variables

-2(2x+1)-(1-8(x-2))+3=0

We multiply parentheses

-4x-(1-8(x-2))-2+3=0



We calculate terms in parentheses: -(1-8(x-2)), so:

1-8(x-2)

determiningTheFunctionDomain
-8(x-2)+1

We multiply parentheses

-8x+16+1

We add all the numbers together, and all the variables

-8x+17

Back to the equation:

-(-8x+17)



We add all the numbers together, and all the variables

-4x-(-8x+17)+1=0

We get rid of parentheses

-4x+8x-17+1=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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