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3-2(2-x)=3x-3(x-2)
We move all terms to the left:
3-2(2-x)-(3x-3(x-2))=0
We add all the numbers together, and all the variables
-2(-1x+2)-(3x-3(x-2))+3=0
We multiply parentheses
2x-(3x-3(x-2))-4+3=0
We calculate terms in parentheses: -(3x-3(x-2)), so:We add all the numbers together, and all the variables
3x-3(x-2)
We multiply parentheses
3x-3x+6
We add all the numbers together, and all the variables
6
Back to the equation:
-(6)
2x-7=0
We move all terms containing x to the left, all other terms to the right
2x=7
x=7/2
x=3+1/2
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