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3-2(2x+5)=2(3x+6)
We move all terms to the left:
3-2(2x+5)-(2(3x+6))=0
We multiply parentheses
-4x-(2(3x+6))-10+3=0
We calculate terms in parentheses: -(2(3x+6)), so:We add all the numbers together, and all the variables
2(3x+6)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
-4x-(6x+12)-7=0
We get rid of parentheses
-4x-6x-12-7=0
We add all the numbers together, and all the variables
-10x-19=0
We move all terms containing x to the left, all other terms to the right
-10x=19
x=19/-10
x=-1+9/10
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