3-2(3x+0.8)=1.5(10-2x)+x

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Solution for 3-2(3x+0.8)=1.5(10-2x)+x equation: 



3-2(3x+0.8)=1.5(10-2x)+x

We move all terms to the left:

3-2(3x+0.8)-(1.5(10-2x)+x)=0

We add all the numbers together, and all the variables

-2(3x+0.8)-(1.5(-2x+10)+x)+3=0

We multiply parentheses

-6x-(1.5(-2x+10)+x)-1.6+3=0



We calculate terms in parentheses: -(1.5(-2x+10)+x), so:

1.5(-2x+10)+x

We add all the numbers together, and all the variables

x+1.5(-2x+10)

We multiply parentheses

x-3x+15

We add all the numbers together, and all the variables

-2x+15

Back to the equation:

-(-2x+15)



We add all the numbers together, and all the variables

-6x-(-2x+15)+1.4=0

We get rid of parentheses

-6x+2x-15+1.4=0

We add all the numbers together, and all the variables

-4x-13.6=0

We move all terms containing x to the left, all other terms to the right

-4x=13.6

x=13.6/-4

x=-3+1/2.5

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