3-2(4n-6)+3n=5(n-3)-2

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Solution for 3-2(4n-6)+3n=5(n-3)-2 equation: 



3-2(4n-6)+3n=5(n-3)-2

We move all terms to the left:

3-2(4n-6)+3n-(5(n-3)-2)=0

We add all the numbers together, and all the variables

3n-2(4n-6)-(5(n-3)-2)+3=0

We multiply parentheses

3n-8n-(5(n-3)-2)+12+3=0



We calculate terms in parentheses: -(5(n-3)-2), so:

5(n-3)-2

We multiply parentheses

5n-15-2

We add all the numbers together, and all the variables

5n-17

Back to the equation:

-(5n-17)



We add all the numbers together, and all the variables

-5n-(5n-17)+15=0

We get rid of parentheses

-5n-5n+17+15=0

We add all the numbers together, and all the variables

-10n+32=0

We move all terms containing n to the left, all other terms to the right

-10n=-32

n=-32/-10

n=3+1/5

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