3-2(b-1)=b-10

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Solution for 3-2(b-1)=b-10 equation:


Simplifying
3 + -2(b + -1) = b + -10

Reorder the terms:
3 + -2(-1 + b) = b + -10
3 + (-1 * -2 + b * -2) = b + -10
3 + (2 + -2b) = b + -10

Combine like terms: 3 + 2 = 5
5 + -2b = b + -10

Reorder the terms:
5 + -2b = -10 + b

Solving
5 + -2b = -10 + b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
5 + -2b + -1b = -10 + b + -1b

Combine like terms: -2b + -1b = -3b
5 + -3b = -10 + b + -1b

Combine like terms: b + -1b = 0
5 + -3b = -10 + 0
5 + -3b = -10

Add '-5' to each side of the equation.
5 + -5 + -3b = -10 + -5

Combine like terms: 5 + -5 = 0
0 + -3b = -10 + -5
-3b = -10 + -5

Combine like terms: -10 + -5 = -15
-3b = -15

Divide each side by '-3'.
b = 5

Simplifying
b = 5

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