3-2(c-3)=3(2c-3)

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Solution for 3-2(c-3)=3(2c-3) equation: 



3-2(c-3)=3(2c-3)

We move all terms to the left:

3-2(c-3)-(3(2c-3))=0

We multiply parentheses

-2c-(3(2c-3))+6+3=0



We calculate terms in parentheses: -(3(2c-3)), so:

3(2c-3)

We multiply parentheses

6c-9

Back to the equation:

-(6c-9)



We add all the numbers together, and all the variables

-2c-(6c-9)+9=0

We get rid of parentheses

-2c-6c+9+9=0

We add all the numbers together, and all the variables

-8c+18=0

We move all terms containing c to the left, all other terms to the right

-8c=-18

c=-18/-8

c=2+1/4

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