3-2(c-3)=3(2c-3)

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Solution for 3-2(c-3)=3(2c-3) equation:



3-2(c-3)=3(2c-3)
We move all terms to the left:
3-2(c-3)-(3(2c-3))=0
We multiply parentheses
-2c-(3(2c-3))+6+3=0
We calculate terms in parentheses: -(3(2c-3)), so:
3(2c-3)
We multiply parentheses
6c-9
Back to the equation:
-(6c-9)
We add all the numbers together, and all the variables
-2c-(6c-9)+9=0
We get rid of parentheses
-2c-6c+9+9=0
We add all the numbers together, and all the variables
-8c+18=0
We move all terms containing c to the left, all other terms to the right
-8c=-18
c=-18/-8
c=2+1/4

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