3-2(c-3)=3(2c-5)

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Solution for 3-2(c-3)=3(2c-5) equation: 



3-2(c-3)=3(2c-5)

We move all terms to the left:

3-2(c-3)-(3(2c-5))=0

We multiply parentheses

-2c-(3(2c-5))+6+3=0



We calculate terms in parentheses: -(3(2c-5)), so:

3(2c-5)

We multiply parentheses

6c-15

Back to the equation:

-(6c-15)



We add all the numbers together, and all the variables

-2c-(6c-15)+9=0

We get rid of parentheses

-2c-6c+15+9=0

We add all the numbers together, and all the variables

-8c+24=0

We move all terms containing c to the left, all other terms to the right

-8c=-24

c=-24/-8

c=+3

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