3-2(d-3)+d=0

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Solution for 3-2(d-3)+d=0 equation: 



3-2(d-3)+d=0

We add all the numbers together, and all the variables

d-2(d-3)+3=0

We multiply parentheses

d-2d+6+3=0

We add all the numbers together, and all the variables

-1d+9=0

We move all terms containing d to the left, all other terms to the right

-d=-9

d=-9/-1

d=+9

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