3-2(x-4)=x(-x-4)

Solution for 3-2(x-4)=x(-x-4) equation:

3-2(x-4)=x(-x-4)

We move all terms to the left:

3-2(x-4)-(x(-x-4))=0

We add all the numbers together, and all the variables

-2(x-4)-(x(-1x-4))+3=0

We multiply parentheses

-2x-(x(-1x-4))+8+3=0


We calculate terms in parentheses: -(x(-1x-4)), so:

x(-1x-4)

We multiply parentheses

-1x^2-4x

Back to the equation:

-(-1x^2-4x)


We add all the numbers together, and all the variables

-(-1x^2-4x)-2x+11=0

We get rid of parentheses

1x^2+4x-2x+11=0

We add all the numbers together, and all the variables

x^2+2x+11=0

a = 1; b = 2; c = +11;
Δ = b2-4ac
Δ = 22-4·1·11
Δ = -40
Delta is less than zero, so there is no solution for the equation