3-2(x2-4x+7)+2x2=5

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Solution for 3-2(x2-4x+7)+2x2=5 equation: 



3-2(x2-4x+7)+2x^2=5

We move all terms to the left:

3-2(x2-4x+7)+2x^2-(5)=0

We add all the numbers together, and all the variables

2x^2-2(+x^2-4x+7)+3-5=0

We add all the numbers together, and all the variables

2x^2-2(+x^2-4x+7)-2=0

We multiply parentheses

2x^2-2x^2+8x-14-2=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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