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3-((2/9)*b) = b*(i/3)-7 // - b*(i/3)-7
3-((2/9)*b)-(b*(i/3))+7 = 0
(-2/9)*b-(b*(i/3))+3+7 = 0
10-1/3*b*i-2/9*b = 0
x należy do R
x in (-oo:+oo)
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