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3-2/9x=1/4x-7
We move all terms to the left:
3-2/9x-(1/4x-7)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 4x-7)!=0We get rid of parentheses
x∈R
-2/9x-1/4x+7+3=0
We calculate fractions
(-8x)/36x^2+(-9x)/36x^2+7+3=0
We add all the numbers together, and all the variables
(-8x)/36x^2+(-9x)/36x^2+10=0
We multiply all the terms by the denominator
(-8x)+(-9x)+10*36x^2=0
Wy multiply elements
360x^2+(-8x)+(-9x)=0
We get rid of parentheses
360x^2-8x-9x=0
We add all the numbers together, and all the variables
360x^2-17x=0
a = 360; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·360·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*360}=\frac{0}{720} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*360}=\frac{34}{720} =17/360 $
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