3-2a-3(1-a)=3(a+2)-5

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Solution for 3-2a-3(1-a)=3(a+2)-5 equation: 



3-2a-3(1-a)=3(a+2)-5

We move all terms to the left:

3-2a-3(1-a)-(3(a+2)-5)=0

We add all the numbers together, and all the variables

-2a-3(-1a+1)-(3(a+2)-5)+3=0

We multiply parentheses

-2a+3a-(3(a+2)-5)-3+3=0



We calculate terms in parentheses: -(3(a+2)-5), so:

3(a+2)-5

We multiply parentheses

3a+6-5

We add all the numbers together, and all the variables

3a+1

Back to the equation:

-(3a+1)



We add all the numbers together, and all the variables

a-(3a+1)=0

We get rid of parentheses

a-3a-1=0

We add all the numbers together, and all the variables

-2a-1=0

We move all terms containing a to the left, all other terms to the right

-2a=1

a=1/-2

a=-1/2

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