3-2m(m+7)=m+14

Solution for 3-2m(m+7)=m+14 equation:

3-2m(m+7)=m+14

We move all terms to the left:

3-2m(m+7)-(m+14)=0

We multiply parentheses

-2m^2-14m-(m+14)+3=0

We get rid of parentheses

-2m^2-14m-m-14+3=0

We add all the numbers together, and all the variables

-2m^2-15m-11=0

a = -2; b = -15; c = -11;
Δ = b2-4ac
Δ = -152-4·(-2)·(-11)
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{137}}{2*-2}=\frac{15-\sqrt{137}}{-4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{137}}{2*-2}=\frac{15+\sqrt{137}}{-4}
$