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3-2x(5-2x)=4x^2+x+-30
We move all terms to the left:
3-2x(5-2x)-(4x^2+x+-30)=0
We add all the numbers together, and all the variables
-2x(-2x+5)-(4x^2+x+-30)+3=0
We use the square of the difference formula
-2x(-2x+5)-(4x^2+x-30)+3=0
We multiply parentheses
4x^2-10x-(4x^2+x-30)+3=0
We get rid of parentheses
4x^2-4x^2-10x-x+30+3=0
We add all the numbers together, and all the variables
-11x+33=0
We move all terms containing x to the left, all other terms to the right
-11x=-33
x=-33/-11
x=+3
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