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3-2x(x+3)=x-18
We move all terms to the left:
3-2x(x+3)-(x-18)=0
We multiply parentheses
-2x^2-6x-(x-18)+3=0
We get rid of parentheses
-2x^2-6x-x+18+3=0
We add all the numbers together, and all the variables
-2x^2-7x+21=0
a = -2; b = -7; c = +21;
Δ = b2-4ac
Δ = -72-4·(-2)·21
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{217}}{2*-2}=\frac{7-\sqrt{217}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{217}}{2*-2}=\frac{7+\sqrt{217}}{-4} $
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