3-2y+4+8y=10y-1

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Solution for 3-2y+4+8y=10y-1 equation: 



3-2y+4+8y=10y-1

We move all terms to the left:

3-2y+4+8y-(10y-1)=0

We add all the numbers together, and all the variables

6y-(10y-1)+7=0

We get rid of parentheses

6y-10y+1+7=0

We add all the numbers together, and all the variables

-4y+8=0

We move all terms containing y to the left, all other terms to the right

-4y=-8

y=-8/-4

y=+2

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