3-3(-2b+2)=4(b-4)+3

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Solution for 3-3(-2b+2)=4(b-4)+3 equation:


Simplifying
3 + -3(-2b + 2) = 4(b + -4) + 3

Reorder the terms:
3 + -3(2 + -2b) = 4(b + -4) + 3
3 + (2 * -3 + -2b * -3) = 4(b + -4) + 3
3 + (-6 + 6b) = 4(b + -4) + 3

Combine like terms: 3 + -6 = -3
-3 + 6b = 4(b + -4) + 3

Reorder the terms:
-3 + 6b = 4(-4 + b) + 3
-3 + 6b = (-4 * 4 + b * 4) + 3
-3 + 6b = (-16 + 4b) + 3

Reorder the terms:
-3 + 6b = -16 + 3 + 4b

Combine like terms: -16 + 3 = -13
-3 + 6b = -13 + 4b

Solving
-3 + 6b = -13 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
-3 + 6b + -4b = -13 + 4b + -4b

Combine like terms: 6b + -4b = 2b
-3 + 2b = -13 + 4b + -4b

Combine like terms: 4b + -4b = 0
-3 + 2b = -13 + 0
-3 + 2b = -13

Add '3' to each side of the equation.
-3 + 3 + 2b = -13 + 3

Combine like terms: -3 + 3 = 0
0 + 2b = -13 + 3
2b = -13 + 3

Combine like terms: -13 + 3 = -10
2b = -10

Divide each side by '2'.
b = -5

Simplifying
b = -5

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