3-3(-6x-4)=7-2(x+6)

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Solution for 3-3(-6x-4)=7-2(x+6) equation: 



3-3(-6x-4)=7-2(x+6)

We move all terms to the left:

3-3(-6x-4)-(7-2(x+6))=0

We multiply parentheses

18x-(7-2(x+6))+12+3=0



We calculate terms in parentheses: -(7-2(x+6)), so:

7-2(x+6)

determiningTheFunctionDomain
-2(x+6)+7

We multiply parentheses

-2x-12+7

We add all the numbers together, and all the variables

-2x-5

Back to the equation:

-(-2x-5)



We add all the numbers together, and all the variables

18x-(-2x-5)+15=0

We get rid of parentheses

18x+2x+5+15=0

We add all the numbers together, and all the variables

20x+20=0

We move all terms containing x to the left, all other terms to the right

20x=-20

x=-20/20

x=-1

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