3-3(10+m)=5(1-2m)-11

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Solution for 3-3(10+m)=5(1-2m)-11 equation: 



3-3(10+m)=5(1-2m)-11

We move all terms to the left:

3-3(10+m)-(5(1-2m)-11)=0

We add all the numbers together, and all the variables

-3(m+10)-(5(-2m+1)-11)+3=0

We multiply parentheses

-3m-(5(-2m+1)-11)-30+3=0



We calculate terms in parentheses: -(5(-2m+1)-11), so:

5(-2m+1)-11

We multiply parentheses

-10m+5-11

We add all the numbers together, and all the variables

-10m-6

Back to the equation:

-(-10m-6)



We add all the numbers together, and all the variables

-3m-(-10m-6)-27=0

We get rid of parentheses

-3m+10m+6-27=0

We add all the numbers together, and all the variables

7m-21=0

We move all terms containing m to the left, all other terms to the right

7m=21

m=21/7

m=3

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