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3-3(10+x)=51(1-2x)-11
We move all terms to the left:
3-3(10+x)-(51(1-2x)-11)=0
We add all the numbers together, and all the variables
-3(x+10)-(51(-2x+1)-11)+3=0
We multiply parentheses
-3x-(51(-2x+1)-11)-30+3=0
We calculate terms in parentheses: -(51(-2x+1)-11), so:We add all the numbers together, and all the variables
51(-2x+1)-11
We multiply parentheses
-102x+51-11
We add all the numbers together, and all the variables
-102x+40
Back to the equation:
-(-102x+40)
-3x-(-102x+40)-27=0
We get rid of parentheses
-3x+102x-40-27=0
We add all the numbers together, and all the variables
99x-67=0
We move all terms containing x to the left, all other terms to the right
99x=67
x=67/99
x=67/99
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