3-3(2y-13)=6(y-1)

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Solution for 3-3(2y-13)=6(y-1) equation: 



3-3(2y-13)=6(y-1)

We move all terms to the left:

3-3(2y-13)-(6(y-1))=0

We multiply parentheses

-6y-(6(y-1))+39+3=0



We calculate terms in parentheses: -(6(y-1)), so:

6(y-1)

We multiply parentheses

6y-6

Back to the equation:

-(6y-6)



We add all the numbers together, and all the variables

-6y-(6y-6)+42=0

We get rid of parentheses

-6y-6y+6+42=0

We add all the numbers together, and all the variables

-12y+48=0

We move all terms containing y to the left, all other terms to the right

-12y=-48

y=-48/-12

y=+4

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