3-3(3n+1)=-6(n-5)

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Solution for 3-3(3n+1)=-6(n-5) equation: 



3-3(3n+1)=-6(n-5)

We move all terms to the left:

3-3(3n+1)-(-6(n-5))=0

We multiply parentheses

-9n-(-6(n-5))-3+3=0



We calculate terms in parentheses: -(-6(n-5)), so:

-6(n-5)

We multiply parentheses

-6n+30

Back to the equation:

-(-6n+30)



We add all the numbers together, and all the variables

-9n-(-6n+30)=0

We get rid of parentheses

-9n+6n-30=0

We add all the numbers together, and all the variables

-3n-30=0

We move all terms containing n to the left, all other terms to the right

-3n=30

n=30/-3

n=-10

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