3-3(k-8)-(k=5)=23

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Solution for 3-3(k-8)-(k=5)=23 equation: 



3-3(k-8)-(k=5)=23

We move all terms to the left:

3-3(k-8)-(k-(5))=0

We multiply parentheses

-3k-(k-5)+24+3=0

We get rid of parentheses

-3k-k+5+24+3=0

We add all the numbers together, and all the variables

-4k+32=0

We move all terms containing k to the left, all other terms to the right

-4k=-32

k=-32/-4

k=+8

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