3-3(z-3)=(3z-5)-7

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Solution for 3-3(z-3)=(3z-5)-7 equation:


Simplifying
3 + -3(z + -3) = (3z + -5) + -7

Reorder the terms:
3 + -3(-3 + z) = (3z + -5) + -7
3 + (-3 * -3 + z * -3) = (3z + -5) + -7
3 + (9 + -3z) = (3z + -5) + -7

Combine like terms: 3 + 9 = 12
12 + -3z = (3z + -5) + -7

Reorder the terms:
12 + -3z = (-5 + 3z) + -7

Remove parenthesis around (-5 + 3z)
12 + -3z = -5 + 3z + -7

Reorder the terms:
12 + -3z = -5 + -7 + 3z

Combine like terms: -5 + -7 = -12
12 + -3z = -12 + 3z

Solving
12 + -3z = -12 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
12 + -3z + -3z = -12 + 3z + -3z

Combine like terms: -3z + -3z = -6z
12 + -6z = -12 + 3z + -3z

Combine like terms: 3z + -3z = 0
12 + -6z = -12 + 0
12 + -6z = -12

Add '-12' to each side of the equation.
12 + -12 + -6z = -12 + -12

Combine like terms: 12 + -12 = 0
0 + -6z = -12 + -12
-6z = -12 + -12

Combine like terms: -12 + -12 = -24
-6z = -24

Divide each side by '-6'.
z = 4

Simplifying
z = 4

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