3-3b+5b=b-2

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Solution for 3-3b+5b=b-2 equation:



3-3b+5b=b-2
We move all terms to the left:
3-3b+5b-(b-2)=0
We add all the numbers together, and all the variables
2b-(b-2)+3=0
We get rid of parentheses
2b-b+2+3=0
We add all the numbers together, and all the variables
b+5=0
We move all terms containing b to the left, all other terms to the right
b=-5

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