3-3b+5b=b-2

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Solution for 3-3b+5b=b-2 equation: 



3-3b+5b=b-2

We move all terms to the left:

3-3b+5b-(b-2)=0

We add all the numbers together, and all the variables

2b-(b-2)+3=0

We get rid of parentheses

2b-b+2+3=0

We add all the numbers together, and all the variables

b+5=0

We move all terms containing b to the left, all other terms to the right

b=-5

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