3-3x-2(1-x)=7(x+3)-28

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Solution for 3-3x-2(1-x)=7(x+3)-28 equation:


Simplifying
3 + -3x + -2(1 + -1x) = 7(x + 3) + -28
3 + -3x + (1 * -2 + -1x * -2) = 7(x + 3) + -28
3 + -3x + (-2 + 2x) = 7(x + 3) + -28

Reorder the terms:
3 + -2 + -3x + 2x = 7(x + 3) + -28

Combine like terms: 3 + -2 = 1
1 + -3x + 2x = 7(x + 3) + -28

Combine like terms: -3x + 2x = -1x
1 + -1x = 7(x + 3) + -28

Reorder the terms:
1 + -1x = 7(3 + x) + -28
1 + -1x = (3 * 7 + x * 7) + -28
1 + -1x = (21 + 7x) + -28

Reorder the terms:
1 + -1x = 21 + -28 + 7x

Combine like terms: 21 + -28 = -7
1 + -1x = -7 + 7x

Solving
1 + -1x = -7 + 7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.
1 + -1x + -7x = -7 + 7x + -7x

Combine like terms: -1x + -7x = -8x
1 + -8x = -7 + 7x + -7x

Combine like terms: 7x + -7x = 0
1 + -8x = -7 + 0
1 + -8x = -7

Add '-1' to each side of the equation.
1 + -1 + -8x = -7 + -1

Combine like terms: 1 + -1 = 0
0 + -8x = -7 + -1
-8x = -7 + -1

Combine like terms: -7 + -1 = -8
-8x = -8

Divide each side by '-8'.
x = 1

Simplifying
x = 1

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