3-4(2c-8)=7c+10

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Solution for 3-4(2c-8)=7c+10 equation: 



3-4(2c-8)=7c+10

We move all terms to the left:

3-4(2c-8)-(7c+10)=0

We multiply parentheses

-8c-(7c+10)+32+3=0

We get rid of parentheses

-8c-7c-10+32+3=0

We add all the numbers together, and all the variables

-15c+25=0

We move all terms containing c to the left, all other terms to the right

-15c=-25

c=-25/-15

c=1+2/3

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