3-4(n-6)=5n+2(n-7)

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Solution for 3-4(n-6)=5n+2(n-7) equation: 



3-4(n-6)=5n+2(n-7)

We move all terms to the left:

3-4(n-6)-(5n+2(n-7))=0

We multiply parentheses

-4n-(5n+2(n-7))+24+3=0



We calculate terms in parentheses: -(5n+2(n-7)), so:

5n+2(n-7)

We multiply parentheses

5n+2n-14

We add all the numbers together, and all the variables

7n-14

Back to the equation:

-(7n-14)



We add all the numbers together, and all the variables

-4n-(7n-14)+27=0

We get rid of parentheses

-4n-7n+14+27=0

We add all the numbers together, and all the variables

-11n+41=0

We move all terms containing n to the left, all other terms to the right

-11n=-41

n=-41/-11

n=3+8/11

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