3-4(z+1)=3z-(2z+z)

Solution for 3-4(z+1)=3z-(2z+z) equation:

Simplifying
3 + -4(z + 1) = 3z + -1(2z + z)

Reorder the terms:
3 + -4(1 + z) = 3z + -1(2z + z)
3 + (1 * -4 + z * -4) = 3z + -1(2z + z)
3 + (-4 + -4z) = 3z + -1(2z + z)

Combine like terms: 3 + -4 = -1
-1 + -4z = 3z + -1(2z + z)

Combine like terms: 2z + z = 3z
-1 + -4z = 3z + -1(3z)

Remove parenthesis around (3z)
-1 + -4z = 3z + -1 * 3z

Multiply -1 * 3
-1 + -4z = 3z + -3z

Combine like terms: 3z + -3z = 0
-1 + -4z = 0

Solving
-1 + -4z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -4z = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -4z = 0 + 1
-4z = 0 + 1

Combine like terms: 0 + 1 = 1
-4z = 1

Divide each side by '-4'.
z = -0.25

Simplifying
z = -0.25