3-4=10+2(9-8c)

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Solution for 3-4=10+2(9-8c) equation: 



3-4=10+2(9-8c)

We move all terms to the left:

3-4-(10+2(9-8c))=0

We add all the numbers together, and all the variables

-(10+2(-8c+9))+3-4=0

We add all the numbers together, and all the variables

-(10+2(-8c+9))-1=0



We calculate terms in parentheses: -(10+2(-8c+9)), so:

10+2(-8c+9)

determiningTheFunctionDomain
2(-8c+9)+10

We multiply parentheses

-16c+18+10

We add all the numbers together, and all the variables

-16c+28

Back to the equation:

-(-16c+28)



We get rid of parentheses

16c-28-1=0

We add all the numbers together, and all the variables

16c-29=0

We move all terms containing c to the left, all other terms to the right

16c=29

c=29/16

c=1+13/16

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