3-5(-x+2)=10+(6-2x)

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Solution for 3-5(-x+2)=10+(6-2x) equation: 



3-5(-x+2)=10+(6-2x)

We move all terms to the left:

3-5(-x+2)-(10+(6-2x))=0

We add all the numbers together, and all the variables

-5(-1x+2)-(10+(-2x+6))+3=0

We multiply parentheses

5x-(10+(-2x+6))-10+3=0



We calculate terms in parentheses: -(10+(-2x+6)), so:

10+(-2x+6)

determiningTheFunctionDomain
(-2x+6)+10

We get rid of parentheses

-2x+6+10

We add all the numbers together, and all the variables

-2x+16

Back to the equation:

-(-2x+16)



We add all the numbers together, and all the variables

5x-(-2x+16)-7=0

We get rid of parentheses

5x+2x-16-7=0

We add all the numbers together, and all the variables

7x-23=0

We move all terms containing x to the left, all other terms to the right

7x=23

x=23/7

x=3+2/7

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