3-5(2-c)=5(9+c)

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Solution for 3-5(2-c)=5(9+c) equation: 



3-5(2-c)=5(9+c)

We move all terms to the left:

3-5(2-c)-(5(9+c))=0

We add all the numbers together, and all the variables

-5(-1c+2)-(5(c+9))+3=0

We multiply parentheses

5c-(5(c+9))-10+3=0



We calculate terms in parentheses: -(5(c+9)), so:

5(c+9)

We multiply parentheses

5c+45

Back to the equation:

-(5c+45)



We add all the numbers together, and all the variables

5c-(5c+45)-7=0

We get rid of parentheses

5c-5c-45-7=0

We add all the numbers together, and all the variables

-52!=0

There is no solution for this equation

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