3-5(2x-2)=-8(x+1)

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Solution for 3-5(2x-2)=-8(x+1) equation: 



3-5(2x-2)=-8(x+1)

We move all terms to the left:

3-5(2x-2)-(-8(x+1))=0

We multiply parentheses

-10x-(-8(x+1))+10+3=0



We calculate terms in parentheses: -(-8(x+1)), so:

-8(x+1)

We multiply parentheses

-8x-8

Back to the equation:

-(-8x-8)



We add all the numbers together, and all the variables

-10x-(-8x-8)+13=0

We get rid of parentheses

-10x+8x+8+13=0

We add all the numbers together, and all the variables

-2x+21=0

We move all terms containing x to the left, all other terms to the right

-2x=-21

x=-21/-2

x=10+1/2

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