3-5(2x-3)=3(3x+2)-7

Solution for 3-5(2x-3)=3(3x+2)-7 equation:

3-5(2x-3)=3(3x+2)-7

We move all terms to the left:

3-5(2x-3)-(3(3x+2)-7)=0

We multiply parentheses

-10x-(3(3x+2)-7)+15+3=0


We calculate terms in parentheses: -(3(3x+2)-7), so:

3(3x+2)-7

We multiply parentheses

9x+6-7

We add all the numbers together, and all the variables

9x-1

Back to the equation:

-(9x-1)


We add all the numbers together, and all the variables

-10x-(9x-1)+18=0

We get rid of parentheses

-10x-9x+1+18=0

We add all the numbers together, and all the variables

-19x+19=0

We move all terms containing x to the left, all other terms to the right

-19x=-19

x=-19/-19

x=1