3-5(4-k)=6(k-3)+6

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Solution for 3-5(4-k)=6(k-3)+6 equation:



3-5(4-k)=6(k-3)+6
We move all terms to the left:
3-5(4-k)-(6(k-3)+6)=0
We add all the numbers together, and all the variables
-5(-1k+4)-(6(k-3)+6)+3=0
We multiply parentheses
5k-(6(k-3)+6)-20+3=0
We calculate terms in parentheses: -(6(k-3)+6), so:
6(k-3)+6
We multiply parentheses
6k-18+6
We add all the numbers together, and all the variables
6k-12
Back to the equation:
-(6k-12)
We add all the numbers together, and all the variables
5k-(6k-12)-17=0
We get rid of parentheses
5k-6k+12-17=0
We add all the numbers together, and all the variables
-1k-5=0
We move all terms containing k to the left, all other terms to the right
-k=5
k=5/-1
k=-5

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