3-5(z+1)=2+(z-4)

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Solution for 3-5(z+1)=2+(z-4) equation:


Simplifying
3 + -5(z + 1) = 2 + (z + -4)

Reorder the terms:
3 + -5(1 + z) = 2 + (z + -4)
3 + (1 * -5 + z * -5) = 2 + (z + -4)
3 + (-5 + -5z) = 2 + (z + -4)

Combine like terms: 3 + -5 = -2
-2 + -5z = 2 + (z + -4)

Reorder the terms:
-2 + -5z = 2 + (-4 + z)

Remove parenthesis around (-4 + z)
-2 + -5z = 2 + -4 + z

Combine like terms: 2 + -4 = -2
-2 + -5z = -2 + z

Add '2' to each side of the equation.
-2 + 2 + -5z = -2 + 2 + z

Combine like terms: -2 + 2 = 0
0 + -5z = -2 + 2 + z
-5z = -2 + 2 + z

Combine like terms: -2 + 2 = 0
-5z = 0 + z
-5z = z

Solving
-5z = z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-5z + -1z = z + -1z

Combine like terms: -5z + -1z = -6z
-6z = z + -1z

Combine like terms: z + -1z = 0
-6z = 0

Divide each side by '-6'.
z = 0

Simplifying
z = 0

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