3-5b+2b=-5+2(b-1)

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Solution for 3-5b+2b=-5+2(b-1) equation: 



3-5b+2b=-5+2(b-1)

We move all terms to the left:

3-5b+2b-(-5+2(b-1))=0

We add all the numbers together, and all the variables

-3b-(-5+2(b-1))+3=0



We calculate terms in parentheses: -(-5+2(b-1)), so:

-5+2(b-1)

determiningTheFunctionDomain
2(b-1)-5

We multiply parentheses

2b-2-5

We add all the numbers together, and all the variables

2b-7

Back to the equation:

-(2b-7)



We get rid of parentheses

-3b-2b+7+3=0

We add all the numbers together, and all the variables

-5b+10=0

We move all terms containing b to the left, all other terms to the right

-5b=-10

b=-10/-5

b=+2

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