3-5b+2b=4-2(1-b)

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Solution for 3-5b+2b=4-2(1-b) equation: 



3-5b+2b=4-2(1-b)

We move all terms to the left:

3-5b+2b-(4-2(1-b))=0

We add all the numbers together, and all the variables

-5b+2b-(4-2(-1b+1))+3=0

We add all the numbers together, and all the variables

-3b-(4-2(-1b+1))+3=0



We calculate terms in parentheses: -(4-2(-1b+1)), so:

4-2(-1b+1)

determiningTheFunctionDomain
-2(-1b+1)+4

We multiply parentheses

2b-2+4

We add all the numbers together, and all the variables

2b+2

Back to the equation:

-(2b+2)



We get rid of parentheses

-3b-2b-2+3=0

We add all the numbers together, and all the variables

-5b+1=0

We move all terms containing b to the left, all other terms to the right

-5b=-1

b=-1/-5

b=1/5

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